Concentrations of Pb2+ and Cl2 at equilibrium

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In summary, the problem involves mixing 50.0 mL of 0.36 M Pb(NO3)2 with 50.0 mL of 1.7 M KCl and calculating the concentrations of Pb2+ and Cl2 at equilibrium. The correct Ksp formula should be used to calculate the concentration of the excess ion after precipitation occurs.
  • #1
magma_saber
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Homework Statement


A solution is prepared by mixing 50.0 mL of 0.36 M Pb(NO3)2 with 50.0 mL of 1.7 M KCl. Calculate the concentrations of Pb2+ and Cl2 at equilibrium. Ksp for PbCl2(s) is 1.6 x 10-5.


Homework Equations


I think its Ksp = [Pb(NO3)2][KCl]2

Pb(NO3)2 = 0.018 mol
KCl = 0.085 mol

Is this right? what do i solve for?
 
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  • #2


Your Ksp is wrong. It should be made of ions concentrations.

Otherwise it is limiting reagent question. Once everything precipitates out, you will be left with the excess of one of the ions involved. Use this concentration to calculate concentration of the other using (correct) Ksp formula.
 
  • #3


I would like to clarify that the equation for calculating the equilibrium concentration of Pb2+ and Cl2 is not Ksp = [Pb(NO3)2][KCl]2. The correct equation is Ksp = [Pb2+][Cl-]^2, where [Pb2+] and [Cl-] represent the equilibrium concentrations of Pb2+ and Cl-, respectively.

Using the given information, we can calculate the equilibrium concentrations as follows:

First, we need to determine the moles of Pb2+ and Cl- in the solution. Since the volumes are the same for both solutions and the molarities are given, we can use the formula moles = molarity x volume (in liters).

Moles of Pb2+ = 0.36 mol/L x 0.050 L = 0.018 mol
Moles of Cl- = 1.7 mol/L x 0.050 L = 0.085 mol

Next, we need to use the stoichiometry of the reaction to determine the equilibrium concentrations of Pb2+ and Cl-. From the balanced equation, we can see that 1 mole of Pb(NO3)2 produces 1 mole of Pb2+ and 2 moles of Cl-. Therefore, the equilibrium concentrations are:

[Pb2+] = 0.018 mol/L
[Cl-] = 2 x 0.085 mol/L = 0.17 mol/L

Finally, we can plug these values into the equation for Ksp to calculate the equilibrium constant:

Ksp = [Pb2+][Cl-]^2
Ksp = (0.018 mol/L)(0.17 mol/L)^2 = 0.0058

Therefore, the equilibrium concentrations of Pb2+ and Cl- in the solution are 0.018 mol/L and 0.17 mol/L, respectively. It is important to note that these concentrations will only remain constant if the conditions of the solution (temperature, pressure, etc.) do not change. Any changes to these conditions can affect the equilibrium concentrations and ultimately, the value of Ksp.
 

Related to Concentrations of Pb2+ and Cl2 at equilibrium

1. What are the factors that affect the equilibrium concentrations of Pb2+ and Cl2?

The equilibrium concentrations of Pb2+ and Cl2 are affected by factors such as temperature, pressure, and the initial concentrations of reactants and products.

2. How does Le Chatelier's principle apply to the concentrations of Pb2+ and Cl2 at equilibrium?

Le Chatelier's principle states that when a system at equilibrium is disturbed, the system will shift in a way to counteract the disturbance. In the case of concentrations of Pb2+ and Cl2 at equilibrium, changes in temperature, pressure, or reactant/product concentrations can cause the system to shift to maintain equilibrium.

3. What is the relationship between the concentrations of Pb2+ and Cl2 at equilibrium?

The concentrations of Pb2+ and Cl2 at equilibrium are directly related to each other through the equilibrium constant, K. As the concentration of one species increases, the concentration of the other species will decrease to maintain the equilibrium constant.

4. How can the concentrations of Pb2+ and Cl2 be calculated at equilibrium?

The concentrations of Pb2+ and Cl2 at equilibrium can be calculated using the equilibrium constant, K, and the initial concentrations of reactants and products. The equation for calculating concentrations at equilibrium is as follows: K = [Pb2+][Cl2] / [PbCl2].

5. What is the significance of the concentrations of Pb2+ and Cl2 at equilibrium?

The concentrations of Pb2+ and Cl2 at equilibrium provide important information about the chemical reaction and the state of the system. They can be used to determine the direction of the reaction, the equilibrium constant, and the extent of the reaction.

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