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\(\displaystyle x = t^3 + 1\)

\(\displaystyle y = t^2 - t\)

Here is what I have so far and where I got stuck.

$x' = 3t^2$

$y' = 2t - 1$

\(\displaystyle

\frac{2t - 1}{3t^2} /9t^4 = \frac{2t - 1}{3t^2} * \frac{1}{9t^4}\)

I'm confused. Am I doing this correctly? I took the derivative of x and y and then did y' / x' / (x')^2