- Thread starter
- #1
Albert
Well-known member
- Jan 25, 2013
- 1,225
Given:
$x,y,z\in\mathbb{N}\text{ and }xy+z=160$
$\text{Compute }\min(x+yz)$
$x,y,z\in\mathbb{N}\text{ and }xy+z=160$
$\text{Compute }\min(x+yz)$
I do find that the Second Partials Test reveals that the critical point is a saddle point.sorry the answer is not correct
the answer is correct ,try to solve it systematically pleaseBest I can do so far (by trial and error) is $(x,y,z) = (26,6,4)$, giving $x+yz = 50$.