Jun 11, 2013 Thread starter #1 A asqw121 New member Jun 11, 2013 5 Integrate (z^3-6z^2+4)dz where the function is any curve joining -1+i to 1. Z is complex number
Jun 11, 2013 Admin #2 M MarkFL Administrator Staff member Feb 24, 2012 13,775 Please post your progress so far so our helpers know exactly where you are stuck or what you may be doing wrong.
Please post your progress so far so our helpers know exactly where you are stuck or what you may be doing wrong.
Jun 12, 2013 Thread starter #3 A asqw121 New member Jun 11, 2013 5 I am trying to first separate them to integrate individual z^3dz, -6z^2dz and 4dz. Line integral γ(t)= t*i+(1-t)*(-1-+i)
I am trying to first separate them to integrate individual z^3dz, -6z^2dz and 4dz. Line integral γ(t)= t*i+(1-t)*(-1-+i)
Jun 12, 2013 #4 ZaidAlyafey Well-known member MHB Math Helper Jan 17, 2013 1,667 There is no need to find a parametric representation of the curve because the function you are integrating has an anti derivative , indeed it is a polynomial . By independence of the path , the integral only depends on the initial and final points .
There is no need to find a parametric representation of the curve because the function you are integrating has an anti derivative , indeed it is a polynomial . By independence of the path , the integral only depends on the initial and final points .