- Thread starter
- #1

#### Petrus

##### Well-known member

- Feb 21, 2013

- 739

Find all roots to \(\displaystyle z^6-2z^3+2=0\)

I can se we there will be 6 roots.

I start with subsitute \(\displaystyle z^3=t\) so we got

\(\displaystyle t^2-2t+2=0\) and we get \(\displaystyle t_1=1+i\) and \(\displaystyle t_2=1-i\)

what shall I do next? Shall I go to polar form?

Regards,