- Thread starter
- #1

#### Raerin

##### Member

- Oct 7, 2013

- 46

a) z^3-1=0

b) 3z^4+i=1-2i

Apparently, the solution for a) is this:

z^3=1

z=1

z=a+bi=1

sqrt(a^2+b^2)=1

I don't understand why a+bi=1 is not the final answer. Why do you have to make it into a modulus?