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- Thread starter wellyn
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We are given:help im stumped on this ((x^{2})/18)-(x/9)=1

\(\displaystyle \frac{x^2}{18}-\frac{x}{9}=1\)

I think I would first multiply through by the lowest common denominator to get rid of the denominators. So, multiplying through by 18, we get:

\(\displaystyle x^2-2x=18\)

Can you proceed?

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You want to take half the coefficient of the linear term (the term with $x$ as a factor) and square it, and add this to both sides. What do you get?no sorry im stumped