# completing the square

#### wellyn

##### New member
help im stumped on this ((x2)/18)-(x/9)=1

#### MarkFL

Staff member
Re: competing the square

help im stumped on this ((x2)/18)-(x/9)=1
We are given:

$$\displaystyle \frac{x^2}{18}-\frac{x}{9}=1$$

I think I would first multiply through by the lowest common denominator to get rid of the denominators. So, multiplying through by 18, we get:

$$\displaystyle x^2-2x=18$$

Can you proceed?

#### wellyn

##### New member
Re: competing the square

no sorry im stumped

#### MarkFL

You want to take half the coefficient of the linear term (the term with $x$ as a factor) and square it, and add this to both sides. What do you get?