- #1
wowowo2006
- 13
- 0
In a QM course,
I learn that an operator can be represented by basis vectors
If the basis vector is complete, the following relation holds
There exist coefficient Mij such that
Sigma Mij |i > < j|. = I , |i> is the basis! and I is the identity matrix
But isn't that in linear algebra
We call the set of basis is complete when
Any vector can be expressed into their linear combination
I wonder why here we seems have 2 definition of completeness
I learn that an operator can be represented by basis vectors
If the basis vector is complete, the following relation holds
There exist coefficient Mij such that
Sigma Mij |i > < j|. = I , |i> is the basis! and I is the identity matrix
But isn't that in linear algebra
We call the set of basis is complete when
Any vector can be expressed into their linear combination
I wonder why here we seems have 2 definition of completeness