Acceleration, Force, and so on

In summary, when the skateboarder gets to the top of the ramp, he has a non-zero vertical velocity left. This vertical velocity is enough to overcome gravity and he becomes airborne.
  • #1
Captain_Insano
4
0
Ok, this seems fairly straight forward, but I can't get my head around it. You have an object (0.3kg) with a vertical (up; positive) velocity of 10 m/s. This object's velocity is supported by a rising piston. Once the piston stops it's movement, how do you determine whether the object has enough momentum to overcome gravity, and jump? What would be the "Force" required to stop this jump? OK, thanks in advance.
 
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  • #2
I don't know what you mean by "overcome gravity". When the piston stops moving, the object still has an upward velocity. It will continue upwards under the influence of gravity, like any object tossed in the air.
 
  • #3
I suppose this may be a better way to explain it. Let's say you have a skateboarder who goes up a ramp:
Skateboarder weighs 70kg
Total vertical height of ramp is 3 meters


One ramp has a linear ramp and a flat top, as follows:


...o o o o o o
...o
...o
..o

(Disregard the "."s, I had to place them in there as a place holder to get this to post correctly)

Disregarding all other forces (friction, air resistance, etc.), and asuming that the velocity up the ramp is constant, how much momentem is required to "jump" at the top of the ramp? As in, if the skateboarder were going slow, he would reach the top, and feel a little less in weight, but would not leave the surface of the flat top. However, if the skateboarder were to be going fast, he would become air borne.

What I'm trying to figure out is what velocity/momentum/whatever is required to break gravity and become airborne. (when will your feet leave the ground in an elevator)

Hope that clarifies, thanks for the response.
 
  • #4
Let me return to your original example (piston and object) and answer the second part of your question.

Think of it this way. The piston cannot stop instantly, it must be deccelerated. If its decceleration is greater than g (the acceleration due to gravity) then the object will separate from the piston. (Just like a tossed object separates from your hand.) To keep the object from leaving the surface, enough force must be applied to it to deccelerate it as much as the piston is deccelerating. (Hope this helps a little.)
 
  • #5
I understand that. However, in the case of the ramp, the lack of support of the object(skateboard) is instantaneous, right? You have a constant velocity of the skateboard, and thus, a constant vertical velocity. Then, at the top of the ramp, what happens? Do you automatically become airborne? And what proof, or formula, shows this? Thanks again.
 
  • #6
Originally posted by Captain_Insano
I understand that. However, in the case of the ramp, the lack of support of the object(skateboard) is instantaneous, right? You have a constant velocity of the skateboard, and thus, a constant vertical velocity. Then, at the top of the ramp, what happens? Do you automatically become airborne? And what proof, or formula, shows this?
First off, the skateboard slows down as it climbs the ramp. (You won't have a constant speed.) When it gets to the top, it will have (we presume) some non-zero vertical component of velocity left. Then, just like any projectile, it will take off. The center of mass of the skater plus board will follow a parabolic path just like any other projectile. Of course, if the velocity at the top is small, the amount of air time will be unimpressive. :smile:

Also, making things more interesting is the fact that the "skater + board" system is not a rigid body. The skater can pull up his legs, etc.
 
  • #7
OK, I think that answers my question. I understand what you mean whe you talk about not being a rigid body, but assuming that it is, it should become airborne, even if at some miniscule degree. So, what would be a good way to show "force" coming off the ramp? Momentum? Velocity? Thanks for all your help, as it has clarified the issue for me.
 

1. What is acceleration?

Acceleration is the rate of change of an object's velocity over time. In other words, it is how quickly an object's speed is changing.

2. How is acceleration calculated?

Acceleration is calculated by dividing the change in an object's velocity by the time interval over which that change occurred. The formula for acceleration is a = (vf - vi) / t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time.

3. What is the relationship between force and acceleration?

According to Newton's second law of motion, the force acting on an object is equal to the mass of the object multiplied by its acceleration. In other words, the greater the force applied to an object, the greater its acceleration will be.

4. How does the direction of a force affect acceleration?

The direction of a force can affect the direction of an object's acceleration. If the force is applied in the same direction as the object's motion, it will increase its speed and therefore its acceleration. If the force is applied in the opposite direction, it will decrease the object's speed and acceleration.

5. Can an object have acceleration without a force acting on it?

Yes, an object can have acceleration without a force acting on it if it is experiencing a change in velocity due to factors such as gravity or friction. This is known as "inertial acceleration" and is described by Newton's first law of motion.

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