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http://mathhelpboards.com/math-notes-49/volumes-pyramids-6131.html

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http://mathhelpboards.com/math-notes-49/volumes-pyramids-6131.html

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- Mar 5, 2012

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Suppose B is the area of the base, H the area of the top, and M the area halfway up.

Then the volume formula is:

$$V = \frac h 6 (B + 4M + H)$$

For instance for a pyramid or cone this is:

$$V = \frac h 6 (B + 4 \cdot \frac B 4 + 0) = \frac 1 3 B h$$