Collision Mechanics and Differential Cross Section

In summary, the problem concerns the collision of a particle on a rigid, fixed disk of radius R with a coefficient of friction of zero and a coefficient of restitution between 0 and 1. The goal is to show that tanαincident = εtanαfinal and to write a program to numerically solve for the differential cross section. This can be done by understanding the physical principles involved and using the Monte Carlo method to approximate the differential cross section.
  • #1
jayqubee
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Homework Statement


The problem concerns the collision of a particle on a rigid, fixed disk of radius R. The coefficient of friction is zero, and the coefficient of restitution is 0 < ε < 1, such that vperpendicular, final = εvperpendicular, initial .
A) Show that tanαincident = εtanαfinal (completed)
Where α is the angle from the velocity vector to the normal vector

B) Write a program to numerically solve for the differential cross section (main problem)


Homework Equations


impact parameter : b
Scattering angle : θ
differential cross section : dσ/dΩ = (b/sinθ)|db/dθ|

The Attempt at a Solution


I honestly do not know where to start here. I solved this problem for hard-sphere scattering but now solving for the impact parameter, b, leads to a dependence on α, which vanished in the hard-sphere case. Any tips on getting this started would be appreciated.
 
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  • #2




Thank you for your post regarding the collision of a particle on a rigid, fixed disk. I would like to offer some suggestions on how to approach this problem and write a program to numerically solve for the differential cross section.

Firstly, it is important to understand the physical principles involved in this problem. The coefficient of friction being zero indicates that the disk is perfectly smooth, and the coefficient of restitution being between 0 and 1 suggests that the collision is not perfectly elastic. This means that there will be some loss of energy during the collision, which will affect the final velocities of the particle.

Now, let's focus on part A of the problem, which asks to show that tanαincident = εtanαfinal. This relationship can be derived from the conservation of momentum and energy. Consider the particle approaching the disk with an initial velocity vperpendicular, initial and an angle αincident with the normal vector of the disk. After the collision, the particle will have a final velocity vperpendicular, final and an angle αfinal with the normal vector. From the conservation of momentum, we can write:

mvperpendicular, initial = mvperpendicular, final

And from the conservation of energy, we can write:

1/2mvperpendicular, initial^2 = 1/2mvperpendicular, final^2

Solving for vperpendicular, final and substituting into the equation for the conservation of momentum, we get:

tanαincident = vperpendicular, initial/vparallel, initial = vperpendicular, final/vparallel, final = tanαfinal

And since we know that vparallel remains constant during the collision, we can write:

tanαincident = εtanαfinal

Moving on to part B, to numerically solve for the differential cross section, we can use the Monte Carlo method. This involves generating a large number of random points within a certain range of the impact parameter b, and then calculating the corresponding scattering angle θ for each point. The differential cross section can then be approximated by taking the average of the values obtained for dσ/dΩ for each point. This process can be repeated multiple times to improve the accuracy of the result.

I hope this helps you get started on solving this problem. If you have any further questions or need clarification, please don't hesitate to ask. Good luck with your program!
 

Related to Collision Mechanics and Differential Cross Section

1. What is collision mechanics?

Collision mechanics is a branch of physics that studies the behavior of particles or objects when they collide with each other. It involves understanding the forces and energy involved in collisions and how they affect the motion and properties of the colliding objects.

2. What is differential cross section?

Differential cross section is a measurement used in collision mechanics to determine the likelihood of a particle scattering in a particular direction after a collision. It takes into account the size and shape of the colliding objects and the angle at which they collide.

3. How is differential cross section related to collision mechanics?

Differential cross section is a crucial aspect of collision mechanics as it provides information about the interaction between particles during a collision. It helps in understanding the underlying mechanisms of the collision and can be used to make predictions about the behavior of particles in future collisions.

4. What factors affect the differential cross section in a collision?

The differential cross section is affected by various factors such as the relative velocity and mass of the colliding objects, the angle of collision, and the properties of the particles such as charge and spin. The shape and size of the colliding objects also play a significant role.

5. How is collision mechanics and differential cross section used in practical applications?

Collision mechanics and differential cross section have numerous applications in various fields such as particle physics, nuclear physics, and astrophysics. They are used to study the behavior of particles in accelerators, understand the structure of atoms and nuclei, and even model the formation of galaxies. They also have practical applications in industries such as materials science and engineering, where collisions between particles are crucial in processes such as welding and sintering.

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