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one_raven
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I am trying to solve gear ratios for a differential gearset when one of the output shaft's rotation is limited...
Let's say:
I have a power split device with an input (A), output1 (B) and output2 (C).
C has a speed limiting mechanism attached to it.
Without limiting the speed of C, ratio A:B is 2:1 and ratio A:C is 2:1.
Let's apply a 300 RPM input to A without the speed limiting device engaged.
B will be spinning at 150 RPM.
C will be spinning at 150 RPM.
Engage the speed limiter and slow C down to 75 RPM.
How do I find the speed of B?
My guess is C(before limiter) - C(after limiter) + B(before limiter)
150-75+150 = 225
So, the functional output gear ratio A:B after limiting C to 150 RPM would be 300/225 or 1.3333:1
I think this is right so far.
Please correct me if I am wrong.
If that is right, what happens if A:B does NOT equal A:C?
If A:B = 3:1 and A:C = 2:1...
If we apply the same 300 RPM input(without the limiter) we will have:
B = 100 RPM
C = 150 RPM
If we slow C down to 75 RPM again how do we solve for B?
If we apply C(before limiter) - C(after limiter) + B(before limiter) we get:
150 - 75 + 100 = 175 RPM @ B
Therefore A:B after the limiter is engaged is 1.714:1
Is this right?
It feels like there is missing something.
Thanks for any help you can give.
Let's say:
I have a power split device with an input (A), output1 (B) and output2 (C).
C has a speed limiting mechanism attached to it.
Without limiting the speed of C, ratio A:B is 2:1 and ratio A:C is 2:1.
Let's apply a 300 RPM input to A without the speed limiting device engaged.
B will be spinning at 150 RPM.
C will be spinning at 150 RPM.
Engage the speed limiter and slow C down to 75 RPM.
How do I find the speed of B?
My guess is C(before limiter) - C(after limiter) + B(before limiter)
150-75+150 = 225
So, the functional output gear ratio A:B after limiting C to 150 RPM would be 300/225 or 1.3333:1
I think this is right so far.
Please correct me if I am wrong.
If that is right, what happens if A:B does NOT equal A:C?
If A:B = 3:1 and A:C = 2:1...
If we apply the same 300 RPM input(without the limiter) we will have:
B = 100 RPM
C = 150 RPM
If we slow C down to 75 RPM again how do we solve for B?
If we apply C(before limiter) - C(after limiter) + B(before limiter) we get:
150 - 75 + 100 = 175 RPM @ B
Therefore A:B after the limiter is engaged is 1.714:1
Is this right?
It feels like there is missing something.
Thanks for any help you can give.