- Thread starter
- #1
Petrus
Well-known member
- Feb 21, 2013
- 739
Somehow he is referring by facit to the textbook.I don't know who/what facit is, but he/she/it is correct. Perhaps if you post your solution, we can discuss it.
What do you mean by rotate? The picture seem nice to mePetrus, I suggest if you are going to upload images that you use some sort of image editing software to rotate the image so that it is the right side up for ease of reading.![]()
If we start with col(a)I don't know who/what facit is, but he/she/it is correct. Perhaps if you post your solution, we can discuss it.
Strange and thanks for doing that! I did not know it needed to be rotated cause it showed correctly for me:S That is strangeYes, the facit refers to the answer key (I have edited the post), and I have rotated, cropped, re-sized and uploaded the new image.
edit: Petrus, on my computer, the image needed to be rotated clockwise 90 degrees.
in exercise 11, I get b is not and w is, but the answer key says b is and w is not...?
Yes, but in post #1 you said that $b$ is not in $\text{col}(A)$.If we start with col(a)
after row reduce we got 1 0 -1|3
----------------------------0 1 2|-1
that means we got infinity soloution, if we set \(\displaystyle x_3=t\) we got \(\displaystyle x_2=-1-2t\) and \(\displaystyle x_1= 3+t\) it indeed got soloution so it is in col(A)
Right?
That'S cause I got actually wrong number in My matrice somehow.. Sorry My bad and now I correctly Solved itYes, but in post #1 you said that $b$ is not in $\text{col}(A)$.