Coefficients of kinetic friction, help PLEASE

In summary, the conversation revolves around solving a problem involving a hockey puck moving on a frozen lake. The initial and final speeds of the puck are given, and the average acceleration is calculated using the kinematic equation V=Vo+at. The distance traveled during the 5.00 second interval is also determined using another kinematic equation. The conversation then shifts to solving for the coefficient of kinetic friction between the puck and the ice. By considering forces and using Newton's second law, it is determined that the normal force is equal to the weight. By dividing the calculated acceleration by the acceleration due to gravity, the average value of the coefficient of kinetic friction is found.
  • #1
myelevatorbeat
55
0
Here is the problem:

A hockey puck is hit on a frozen lake and starts moving with a speed of 13.0 m/s. Five seconds later, its speed is 5.20 m/s.

(a) What is its average acceleration?

I used the kinematic equation V=Vo+at to find the accerlation which came out to be -1.56 m/s^2 (this answer is right).

(b) What is the average value of the coefficient of kinetic friction between puck and ice?

(c) How far does the puck travel during the 5.00 s interval? m

I used X-Xo=1/2[V+Vo]t to solve this and got 45.5 m, which is right.


So basically, I'm stuck on part B of this problem. I don't remember my professor going over how to solve this particular type of problem in class so I was hoping someone here could get me started. I'm not asking for the answer, just an explanation of how to solve Part B.
 
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  • #2
Think about forces and Newton's second law. You have already figured out the acceleration. What's the definition of kinetic friction?
 
  • #3
I assume I would make F=ma equal to Fk=uN.

However, I don't see how I can do this since the mass wasn't given.
 
  • #4
OK, but what is the normal force equal to?
 
  • #5
The normal force is equal to the weight, which is mass x gravity, but again I get lost because I don't have the mass.
 
  • #6
Wait, nevermind. I got it. I divided acceleration/gravity and came out with the answer.

Thanks for your help though!
 
  • #7
Good!

You're welcome :smile:
 

Related to Coefficients of kinetic friction, help PLEASE

1. What is the definition of coefficient of kinetic friction?

The coefficient of kinetic friction is a dimensionless constant that represents the amount of friction between two surfaces in contact when they are in relative motion.

2. How is the coefficient of kinetic friction calculated?

The coefficient of kinetic friction is calculated by dividing the force of kinetic friction by the normal force between the two surfaces. This can be represented by the formula μk = Fk/Fn.

3. What factors affect the coefficient of kinetic friction?

The coefficient of kinetic friction can be affected by various factors such as the nature of the surfaces in contact, the roughness of the surfaces, the temperature, and the presence of any lubricants or fluids between the surfaces.

4. What is the difference between kinetic friction and static friction?

Kinetic friction is the force that acts between two surfaces in contact when they are in motion, while static friction is the force that acts between two surfaces in contact when they are at rest. The coefficient of kinetic friction is usually lower than the coefficient of static friction.

5. How is the coefficient of kinetic friction used in real-life applications?

The coefficient of kinetic friction is used in various real-life applications, such as designing car tires with optimal grip, calculating the stopping distance of a vehicle, and determining the amount of force required to move an object on a surface. It is also important in understanding the efficiency of machines and designing efficient braking systems.

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