Classes of polynomials whose roots form a cyclic group

In summary, cyclotomic polynomials are the only polynomials with a characteristic above 2. However, they have odd degree except for Phi_1(x) and Phi_2(x). Even if we include 1 in the set of roots of a cyclotomic polynomial, it's not a proper subgroup.
  • #1
burritoloco
83
0
Hi, I'm currently doing a project and this topic has come up. Are there any known famous classes of polynomials (besides cyclotomic polynomials) that fit that description? In particular, I'm more interested in the case where the polynomials have odd degree. I know for example that the roots of cyclotomic polynomials form cyclic groups, but they have even degree except for Phi_1(x) and Phi_2(x). Many thanks!
 
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  • #2
Hmm, because all the finite multiplicative subgroups of the complex numbers are precisely the cyclic groups generated by primitive roots of unity, wouldn't this imply that the only polynomials with that characteristic (above) are the cyclotomic polynomials? How about when considering polynomials over finite fields instead?
 
  • #3
Hi burritoloco! :smile:

Do you mean that the roots must form a cyclic group, or that the roots must generate a cyclic group? Judging from your talk about the cyclotomic polynomials, I guess the latter.

Well, when working over a finite field, then every polynomial [itex]P(X)\in \mathbb{F}_p(X)[/itex] with [itex]P(X)\notin (X)[/itex] will generate a cyclic group!

Also, in every field with characteristic p, the Artin-Schreier polynomial

[tex]X^p-X+a[/tex]

with a nonzero, will generate a cyclic group.
 
  • #4
Hi micromass and thanks for your reply!

I initially meant "form" but I now realize that 1 is not a root of cyclotomic polynomials except for Phi_1(x), so its roots cannot form a group! Thus "generate" seems to be the right word. So let me rephrase. Let's say we make a set with all the roots of a polynomial, and 1. For what polynomials will this set be a cyclic group?
 
  • #5
Well, then I guess the only polynomials that satisfy this are some divisors of [itex]X^n-1[/itex]...
 
  • #6
I see :). What if instead of taking a cyclotomic polynomial as such a divisor, we take an irreducible factor of it (so over finite fields). Could it still satisfy the above?
 
  • #7
By the above I meant my previous post...
 
  • #8
Of course, the roots of an irreducible factor of a cyclotomic polynomial form a subset of the cyclic group generated by the corresponding primitive root of unity. The question is: when we include 1 in this subset, can it be a cyclic subgroup? When does this happen?
 
  • #9
Hmm, I'm afraid not. The only way this subset is a proper subgroup of the cyclic group generated by an nth primitive root of unity, is if it's generated by a non-nth primitive root, say an mth primitive root of unity. So the corresponding polynomial would still be the mth-cyclotomic polynomial not necessarily irreducible over the finite field. Moreover, this polynomial would still have even degree (if it's not Phi_1(x), Phi_2(x)). So no luck!
 
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Related to Classes of polynomials whose roots form a cyclic group

1. What is a cyclic group in the context of polynomials?

A cyclic group is a mathematical concept that describes a set of elements that can be generated by repeatedly applying a single operation to a starting element, called a generator. In the context of polynomials, a cyclic group is a set of polynomials whose roots can be generated by repeatedly applying a single operation, such as addition or multiplication, to a starting polynomial.

2. How can a polynomial have a cyclic group of roots?

A polynomial can have a cyclic group of roots if it meets certain criteria. First, the polynomial must have a finite number of distinct roots. Second, these roots must be related in a specific way, such as being evenly spaced around a circle or forming a regular polygon. Finally, the polynomial must be irreducible, meaning it cannot be factored into polynomials of lower degree with rational coefficients.

3. What are some examples of classes of polynomials whose roots form a cyclic group?

One example is the class of cyclotomic polynomials, which have roots that form a regular polygon on the complex plane. Another example is the class of Chebyshev polynomials, which have roots that form a regular polygon on the real number line. Additionally, certain families of generalized cyclotomic polynomials and Lucas polynomials also have roots that form cyclic groups.

4. Why is the study of polynomials with cyclic group roots important?

The study of polynomials with cyclic group roots is important in many areas of mathematics, including number theory, algebra, and geometry. These polynomials have connections to topics such as prime numbers, group theory, and geometric constructions. Furthermore, understanding the properties of these polynomials can provide insight into the structure and behavior of more complex mathematical objects.

5. Are there any real-world applications of polynomials with cyclic group roots?

Yes, there are several real-world applications of polynomials with cyclic group roots. One example is in coding theory, where certain cyclic codes are constructed using polynomials with cyclic group roots. These codes are used in error-correcting systems for data transmission and storage. Additionally, the properties of these polynomials have been used in cryptography, specifically in the design of secure hash functions.

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