- #1
Kara386
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Homework Statement
I think this is a 'magnetic mirror' question - the field lines converge on the z axis.
For a particle moving into an area of increasing field strength, where the field lines converge. Assume the ##B## field is rotationally symmetric about the ##z## axis, with ##B = B_z \hat{z}## being the main field, ##B_r## pointing inwards and ##B_φ = 0## (cylindrical coordinates). Use the fact that this field has ##div B = 0## to find ##B_r##, and show that ##\frac{v_p^2}{B}## is a conserved quantity by considering the Lorentz force.
Homework Equations
The Attempt at a Solution
I'm a little rusty on cylindrical co-ords, but I think the field can be written as
##B = B_r \hat{r} + B_z \hat{z}##
In cylindrical co-ordinates the divergence of the field is (using the fact it's divergence free):
##\frac{1}{r}\frac{\partial{(r B_r)}}{\partial r} + \frac{\partial B_z}{\partial z} = 0##
With a converging field clearly ##B_z = B(z)##, and using the product rule on the first term:
##\frac{\partial B_r}{\partial r} + B_r + \frac{\partial B_z}{\partial z} = 0##
Which gives
##B_r = -\frac{\partial B_r}{\partial r} - \frac{\partial B_z}{\partial z}##
The equation of motion for this system is
##m\frac{dv}{dt} = q(v \times B) ##
Which can be calculated from the determinant
##m\frac{dv}{dt} = q
\left| \begin{array}{ccc}
\hat{r} & \hat{\theta} & \hat{z} \\
v_r & v_{\theta} & v_z \\
B_r & 0 & B_z\end{array} \right|##
##= qv_{\theta} B_z \hat{r} - \hat{\theta} q(vB_z - v_zB_r) - \hat{z} q v_{\theta} B_r##
Can't see how to show from there that the quantity ##\frac{v_p^2}{B}## is conserved. Not even sure that determinant is right! Thanks for any help! :)