- #1
V0ODO0CH1LD
- 278
- 0
If h(x) = ax, g(x) = bx and f(x) = g(h(x)).
Wouldn't h'(x) = a? And g'(x) = b? And f'(x) = ab?
But the chain rule says f'(x) must equal h'(x)g'(h(x)), so that means f'(x) = ab(ax) = (a^2)bx.
Am I missing something obvious?
Wouldn't h'(x) = a? And g'(x) = b? And f'(x) = ab?
But the chain rule says f'(x) must equal h'(x)g'(h(x)), so that means f'(x) = ab(ax) = (a^2)bx.
Am I missing something obvious?