Centripetal Motion Velocity vs. Position Angle Assignment

In summary, the conversation discusses how to prove that the angle between two position vectors and two instantaneous velocity vectors in uniform circular motion is equal, without using calculus. There is no given angle, and the question asks to show the equality between θ1 and θ2. The participants suggest drawing a diagram to visualize the relationship between the position and velocity vectors, and mention that in circular motion, the velocity vector is always normal to the position vector. This leads to the conclusion that the normal of two intersecting lines at an angle θ will have an angle of 90 degrees between them. Therefore, the angles between the position vectors and velocity vectors must also be equal.
  • #1
burtonjib
3
0
1. Show that the angle between two position vectors is equal to the angle between two instantaneous velocity vectors eg. v1 and v2 when v1 and v2 are conncected tail to tail in a uniform circle. No angles are given, it is just general.



2. Has to be proven without calculus. No information is given other than the fact that the circle is uniform and therefore the speed is constant.



3. I didn't attempt the question because I'm not exactly sure how to go by proving that the angles are equal.

 
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  • #2
Do I understand you to be describing two particles in circular motion about a common central point? If so, then what is the angle between each particle's position vector and its velocity vector?
 
  • #3
Yes that's exactly it. No angle was given though, the question is just asking to prove that the angle between position vectors is equal to that between the velocity vectors.
 
  • #4
Try drawing a diagram. Draw arbitrary position vectors from a common point and then draw a velocity vector from the head of each position vector. Keep in mind that circular motion makes each velocity vector normal to its corresponding position vector.
 
  • #5
I don't really see how that would show the equality between θ1 and θ2
 
  • #6
If two lines intersect at an angle θ, at what angle do their normals intersect?
 

Related to Centripetal Motion Velocity vs. Position Angle Assignment

1. What is centripetal motion velocity?

Centripetal motion velocity refers to the speed at which an object is moving towards the center of a circular path. It is the magnitude of the velocity vector, which is always directed towards the center of the circle.

2. How is centripetal motion velocity related to position angle?

The position angle is the angle between the radius of the circle and a reference line, usually the x-axis. Centripetal motion velocity is directly related to the position angle, as it determines the direction of the velocity vector towards the center of the circle.

3. What factors affect the centripetal motion velocity?

The centripetal motion velocity is affected by the radius of the circle, the mass of the object, and the speed at which the object is moving. The greater the radius and the speed, the higher the centripetal motion velocity will be. However, a larger mass will result in a slower velocity.

4. How is centripetal motion velocity calculated?

The centripetal motion velocity can be calculated using the formula v = √(rω), where v is the velocity, r is the radius of the circle, and ω is the angular velocity. Alternatively, it can also be calculated as v = r * θ, where θ is the angular displacement.

5. What is the relationship between centripetal motion velocity and centripetal acceleration?

Centripetal motion velocity and centripetal acceleration are directly proportional to each other. Centripetal acceleration is the rate of change of the velocity, and it is given by a = v^2 / r, where a is the acceleration, v is the velocity, and r is the radius of the circle. This means that as the velocity increases, the centripetal acceleration also increases, resulting in a larger centripetal motion velocity.

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