Centripetal Acceleration/Gravity Problem

In summary: I DOING THIS RIGHT?In summary, a circular "space hotel" in orbit around the Earth with a diameter of 355m wants to produce "fake gravity" along the outer rim by rotating it at a speed that will create a centripetal acceleration of 9.81m/s^2. To find the tangential speed, the formula v=at and the angular velocity formula ω=ø/t can be used. At this speed, the station's angular velocity can be found using the formula ac=v^2/r=rω^2. If someone is 77m from the outer rim, they will experience the same amount of "gravity" as they would on Earth. Moving from the rim towards the central hub will
  • #1
Drokro0707
1
0

Homework Statement


A circular "space hotel" in orbit around the Earth has a diameter of 355m. In order to produce "fake gravity" along the outer rim, it is desired to rotate it at a speed that will produce a centripetal acceleration of 9.81m/s^2. Note the geometry: people walking on the inside of the outer rim will weigh the same as if they were on Earth. Drawing will help.

a)Find the tangential speed of a point on the rim when the station is producing the required centripetal acceleration.

b)Find the stations angular velocity under those conditions, in radians per second.

c)If you're "below deck" at a point 77m from the outer rim, how much "gravity" will you experience?

d)If you start moving from the rim toward the central hub of the space station, what will it feel like? How will perception change as you move?

Homework Equations



v=at
a=dv/dt
ac=v^2/r=rω^2
ω=ø/t

The Attempt at a Solution


Im assuming that the centripetal acceleration formula would be used to solve for part a and then the angular velocity formula would help solve part b. For part c since gravity is mentioned I don't know what to do exactly but I think that's where the 9.81m/s^2 would come into play. As for part d, I have not the slightest clue.
 
Last edited by a moderator:
Physics news on Phys.org
  • #2
Drokro0707 said:

Homework Statement


A circular "space hotel" in orbit around the Earth has a diameter of 355m. In order to produce "fake gravity" along the outer rim, it is desired to rotate it at a speed that will produce a centripetal acceleration of 9.81m/s^2. Note the geometry: people walking on the inside of the outer rim will weigh the same as if they were on Earth. Drawing will help.

a)Find the tangential speed of a point on the rim when the station is producing the required centripetal acceleration.

b)Find the stations angular velocity under those conditions, in radians per second.

c)If you're "below deck" at a point 77m from the outer rim, how much "gravity" will you experience?

d)If you start moving from the rim toward the central hub of the space station, what will it feel like? How will perception change as you move?


Homework Equations



v=at
a=dv/dt
ac=v^2/r=rω^2
ω=ø/t

The Attempt at a Solution


Im assuming that the centripetal acceleration formula would be used to solve for part a and then the angular velocity formula would help solve part b. For part c since gravity is mentioned I don't know what to do exactly but I think that's where the 9.81m/s^2 would come into play. As for part d, I have not the slightest clue.
You have the right formula for ac. Use ω = dø/dt = Δø/Δt (ω being constant).

At what value of ω does the centripetal acceleration = the acceleration due to gravity on the Earth surface?

d) is a little tricky to analyse. Do an experiment: spin a playground merry-go-round, jump on the outside and then move toward the centre. Will the centripetal force change? How? What will happen to your tangential speed? What effect will that change have?

AM
 

Related to Centripetal Acceleration/Gravity Problem

1. What is centripetal acceleration?

Centripetal acceleration is the acceleration that an object experiences when it moves in a circular path. It is always directed towards the center of the circle and its magnitude depends on the object's speed and the radius of the circle.

2. How is centripetal acceleration related to gravity?

Centripetal acceleration is related to gravity because gravity is the force that keeps objects in circular motion. In other words, gravity provides the centripetal force that causes an object to accelerate towards the center of the circle.

3. How is centripetal acceleration calculated?

Centripetal acceleration can be calculated using the formula a = v^2/r, where a is the centripetal acceleration, v is the velocity of the object, and r is the radius of the circle. Alternatively, it can also be calculated using the formula a = ω^2r, where ω is the angular velocity of the object.

4. What is the difference between centripetal acceleration and tangential acceleration?

Centripetal acceleration is the acceleration towards the center of a circle, while tangential acceleration is the acceleration in the direction of motion. In circular motion, the tangential acceleration is always perpendicular to the centripetal acceleration.

5. How does centripetal acceleration affect the motion of objects?

Centripetal acceleration causes objects to move in circular paths. It is responsible for keeping objects in circular motion and preventing them from moving in a straight line. The magnitude of the centripetal acceleration also affects the speed at which an object travels in a circular path.

Similar threads

  • Introductory Physics Homework Help
Replies
1
Views
970
  • Introductory Physics Homework Help
Replies
5
Views
2K
  • Introductory Physics Homework Help
Replies
28
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
3K
  • Introductory Physics Homework Help
Replies
4
Views
4K
  • Introductory Physics Homework Help
Replies
8
Views
2K
  • Introductory Physics Homework Help
Replies
3
Views
812
Back
Top