Centre of mass of a solid hemisphere. What am I doing wrong?

[Marvin94]

I have to calculate the centre of mass of the drawn hemisphere. I don't understand where I make mistakes. The process I followed on the above image is the following:

(I) Here I simply translated position vector components from cartesian to polar coordinates.
(II) Formula of x-component of position vector of centre of gravity (this position vector clearly lies on the x-axis, so I'm interested only in this component)
(III) This is the volume element for polar coordinates system.

After that, I just put (III) into (II).

The problem is that, the result of the last (triple) integral (computable easily with wolfram alpha) seems to result zero! I thought that the mistake could be in the integration limits, but they look to be correct. Where am I doing wrong?

Thank you very much in advance.

 

[BvU]

Hi Marv,

Check your integration limits anyway. Looks to me that you aren't integrating over the righthand half of the sphere...

 

[Marvin94]

I tried to understand why what I wrote should be wrong, but I don't see the mistake. Which limits do you think are correct?

 

[BvU]

Well, you haven't shown what ##\theta## ande ##\phi## are, so I can't tell, but you can !
[edit] but it's implicit in your coordinate transformation. Check if Rx > 0 always during the integration...

 

[Marvin94]

θ = angle between position vector and x-axis
ϕ = angle between position vector and z-axis

 

[Marvin94]

I used an ambiguous notation: I should precise, that the initial vector r (see (I) ) is a general position vector. The vector rx I use after that refers to the position vector of the centre of mass (not the general one!).

 

[BvU]

Check if your rx is always positive.
Check if your ry really runs from -1 to +1
Check if your rz really runs from -1 to +1

As an exercise, do the integration yourself, instead of with the Wolfram crutches.

 

[BvU]

θ = angle between position vector and x-axis
ϕ = angle between position vector and z-axis

Nope. Not if ##z = r\cos \theta##

 

[theodoros.mihos]

Check terms in $$ r_{cm} = \frac{1}{V}\int\int\int \,r\,dV $$

 

[Marvin94]

Thanks you all a lot :)