Centre of gravity shifted to what position?

In summary: They went on to state that " centers of gravity lie at a distance of 5/12 of the side of the original square from each uncut side."
  • #1
Benjamin_harsh
211
5
Homework Statement
A square sheet of metal has a square of one quarter of the original area cut from one corner as shown in the figure. Which of the following statements is true about the position of the centre of gravity of the remaining portion of the sheet?
Relevant Equations
original side of the square = ##2x##
A square sheet of metal has a square of one quarter of the original area cut from one corner as shown in the figure. Which of the following statements is true about the position of the centre of gravity of the remaining portion of the sheet?

245727


a) center of gravity lies at a distance of 5/12 of the side of the original square from each uncut side.
b) center of gravity lies at a distance 7/12 of the side of the original square from each uncut side.
c) center of gravity lies at a distance of 63/4 of the side of the original square from each uncut side.
d) None of these.

Solution:

245729


##\overline X = \large \frac{A_{1}\overline{x_{1}} - A_{1}\overline{x_{2}}}{A_{1}-A_{2}} =
\frac{(4x^{2}).(x) - (x^{2})(1.5x)}{4x^{2}-x^{2}}##

##\overline X = \large\frac{5x}{6} = \frac{5}{12}\normalsize(2x)####\overline Y = \large\frac{A_{1}\overline{y_{1}} - A_{1}\overline{y_{2}}}{A_{1}-A_{2}}
= \frac{5x}{6} = \frac{5}{12}\normalsize(2x)##

original side of the square = ##2x##

Why they didn't continue after this step: ##\frac{5}{12}(2x)##?
 
Last edited:
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  • #2
Sorry, your solution is unreadable.
 
  • #3
mjc123 said:
Sorry, your solution is unreadable.
Now I edited clearly. Please see it.
 
  • #4
You have two steps that end with 5/12(2x). Which is the one that "they" didn't continue after? What continuation do you think is necessary? You have the information to answer the question.
 
  • #5
mjc123 said:
You have the information to answer the question.
Answer is: center of gravity lies at a distance of ##\frac{5}{12}## of the side of the original square from each uncut side.

Can you show center of gravity before and after cut by drawing the diagram?
 
  • #6
A is original CG, B the CG after cut.
squares.png
 
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  • #7
I am confused at this sentence: ##\frac{5}{12}## of the side of the original square from each uncut side.

How to understand it?
 
  • #8
Benjamin_harsh said:
I am confused at this sentence: ##\frac{5}{12}## of the side of the original square from each uncut side.

How to understand it?
5/12 of the way from the left (uncut) side toward the right (cut) side.
5/12 of the way from the bottom (uncut) side toward the top (cut) side.
 
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  • #9
Benjamin_harsh said:
Problem Statement: A square sheet of metal has a square of one quarter of the original area cut from one corner as shown in the figure. Which of the following statements is true about the position of the centre of gravity of the remaining portion of the sheet?
Relevant Equations: original side of the square = ##2x##

A square sheet of metal has a square of one quarter of the original area cut from one corner as shown in the figure. Which of the following statements is true about the position of the centre of gravity of the remaining portion of the sheet?

View attachment 245727

a) center of gravity lies at a distance of 5/12 of the side of the original square from each uncut side.
b) center of gravity lies at a distance 7/12 of the side of the original square from each uncut side.
c) center of gravity lies at a distance of 63/4 of the side of the original square from each uncut side.
d) None of these.

Solution:

View attachment 245729

##\overline X = \large \frac{A_{1}\overline{x_{1}} - A_{1}\overline{x_{2}}}{A_{1}-A_{2}} =
\frac{(4x^{2}).(x) - (x^{2})(1.5x)}{4x^{2}-x^{2}}##

##\overline X = \large\frac{5x}{6} = \frac{5}{12}\normalsize(2x)####\overline Y = \large\frac{A_{1}\overline{y_{1}} - A_{1}\overline{y_{2}}}{A_{1}-A_{2}}
= \frac{5x}{6} = \frac{5}{12}\normalsize(2x)##

original side of the square = ##2x##

Why they didn't continue after this step: ##\frac{5}{12}(2x)##?
The question asked was "which of these is correct:
a) center of gravity lies at a distance of 5/12 of the side of the original square from each uncut side.
b) center of gravity lies at a distance 7/12 of the side of the original square from each uncut side.
c) center of gravity lies at a distance of 63/4 of the side of the original square from each uncut side.
d) None of these.
By writing the coordinates of the center of gravity as "(5/12)2x" they thought it was not necessary to say that "a" is correct.
 

Related to Centre of gravity shifted to what position?

1. What is the centre of gravity?

The centre of gravity is the point at which the entire weight of an object is considered to be concentrated. It is the average location of the weight of an object.

2. How is the centre of gravity determined?

The centre of gravity can be determined by finding the point at which an object would balance if it were suspended. It can also be calculated using the weight and position of different parts of the object.

3. How does the centre of gravity affect stability?

The position of an object's centre of gravity plays a crucial role in its stability. If the centre of gravity is located within the base of an object, it will be stable. If it is located outside the base, the object will be less stable and may topple over.

4. Can the centre of gravity be shifted?

Yes, the centre of gravity can be shifted by changing the weight distribution of an object. This can be done by adding or removing weight from different parts of the object or by changing its shape.

5. What happens when the centre of gravity is shifted to an extreme position?

When the centre of gravity is shifted to an extreme position, the object becomes less stable and may topple over. This is because the weight is no longer evenly distributed and the object's base of support is reduced.

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