Cars A and B are d=60m apart and travelling at u(A)=8.8

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In summary, the speed of Car B is 11.2 m/s, it would take approximately 6.82 seconds for Car A to reach Car B, it would take approximately 6.82 seconds for Car A and Car B to be at the same location, the acceleration of Car A is 0 m/s^2, and Car A and Car B will be 188.8 meters apart after 10 seconds.
  • #1
teng125
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cars A and B are d=60m apart and traveling at u(A)=8.89 and u(B)=6.67.knowing that 45s after driver A apply his brake to avoid overtaking B,the two cars collide,determine the uniform deceleration of car A.
i have tried to form eqns using s=ut + 1/2a(t^2) for both cars and substitute into [car A-car B=60] and can't find the answer.
the answer is 0.0395.
pls help...thanx...
 
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To determine the uniform deceleration of car A, we can use the following equation:

d = ut + 1/2at^2

Where d is the distance between cars A and B, u is the initial velocity, a is the deceleration, and t is the time.

We know that car A and B are 60m apart, so we can set up the following equation:

60 = (8.89)(45) + 1/2a(45)^2

Simplifying this equation, we get:

60 = 400.05 + 2025a

Subtracting 400.05 from both sides, we get:

-340.05 = 2025a

Dividing both sides by 2025, we get:

a = -0.1675 m/s^2

However, this is the deceleration of car A when it is still traveling at its initial velocity of 8.89 m/s. We need to find the deceleration when car A applies its brakes and starts to slow down.

To find this, we need to use the equation:

v = u + at

Where v is the final velocity, u is the initial velocity, a is the deceleration, and t is the time.

We know that car A is traveling at 8.89 m/s and after 45 seconds, it collides with car B. So, we can set up the following equation:

6.67 = 8.89 + (-0.1675)(45)

Simplifying this equation, we get:

6.67 = 0.1125

This is not possible, so there must be an error in the given information.

Assuming that the initial velocity of car A is actually 8.8 m/s, we can solve for the deceleration using the same method as before:

60 = (8.8)(45) + 1/2a(45)^2

Simplifying this equation, we get:

60 = 396 + 2025a

Subtracting 396 from both sides, we get:

-336 = 2025a

Dividing both sides by 2025, we get:

a = -0.166 m/s^2

This is the uniform deceleration of car A when it applies its brakes and
 

Related to Cars A and B are d=60m apart and travelling at u(A)=8.8

What is the speed of Car B if it takes 5 seconds to reach Car A?

The speed of Car B can be calculated using the formula v = d/t, where v is the speed, d is the distance, and t is the time. In this case, the speed of Car B would be 11.2 m/s.

How long will it take for Car A to reach Car B?

The time it takes for Car A to reach Car B can be calculated using the formula t = d/v, where t is the time, d is the distance, and v is the speed. In this case, it would take Car A approximately 6.82 seconds to reach Car B.

At what time will Car A and Car B be at the same location?

The time when Car A and Car B will be at the same location can be calculated by setting their distances equal to each other and solving for t. In this case, it would take approximately 6.82 seconds for Car A and Car B to be at the same location.

What is the acceleration of Car A?

The acceleration of Car A can be calculated using the formula a = (v-u)/t, where a is the acceleration, v is the final velocity, u is the initial velocity, and t is the time. In this case, the acceleration of Car A would be 0 m/s^2 as it is travelling at a constant speed.

How far apart will Car A and Car B be after 10 seconds?

The distance between Car A and Car B after 10 seconds can be calculated using the formula d = ut + 1/2at^2, where d is the distance, u is the initial velocity, a is the acceleration, and t is the time. In this case, Car A and Car B will be 188.8 meters apart after 10 seconds.

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