Capacitance of a capacitor in which the first plate is (-)vely charged

In summary, when an isolated positively charged conductor is brought close to an identical conductor and earthed, the second conductor develops a negative charge, reducing the net electric potential on the surface of the first conductor and increasing its capacitance. However, the self capacitance of the second conductor would be the same as the self capacitance of the Earth, around 700µF. The self capacitance of the first conductor would also decrease if it is negatively charged and another identical conductor is brought close to it. This is due to the mutual capacitance between the two objects.
  • #1
shiv_99
6
0
I have read that if we have an isolated positively charged conductor, we can increase itself capacitance by bringing an identical conductor close to it and then earthing it, so, that the second conductor develops a negative charge and thereby helps in reducing the net electric potential on the surface of the first conductor. (and so capacitance of conductor will increase as V will decrease).

BUT my question is
a)what happens to the self capacitance of the second conductor (does it become infinite? if so then why does the capacitance of the capacitor as a whole does not equal infinity!)

b)if the first conductor is negatively charged and another identical conductor is brought close to it, won't the self-capacitance of the first conductor decrease.
 
Physics news on Phys.org
  • #2
Where did you read that? I think this is only a question of definitions.
Self capacitance describes the ratio of charge to absolute potential for an isolated object. If you introduce a nearby earthed conductor, then you would not only be seeing 'self' capacitance but the mutual capacitance of the two objects.
The "self capacitance of the second conductor" would be the same as the self capacitance of the Earth, to which it's connected. This is about 700µF, iirc.
 

Related to Capacitance of a capacitor in which the first plate is (-)vely charged

1. What is capacitance?

Capacitance is a measure of the ability of a capacitor to store electric charge. It is represented by the symbol C and is measured in units of farads (F).

2. How is capacitance affected by the charge on the first plate?

The capacitance of a capacitor is directly proportional to the charge on the first plate. This means that as the charge on the first plate increases, the capacitance also increases.

3. What happens to the capacitance if the charge on the first plate is negative?

The sign of the charge on the first plate does not affect the capacitance. Whether the charge is positive or negative, the capacitance remains the same.

4. How can the capacitance of a capacitor with a negatively charged first plate be calculated?

The capacitance of a capacitor with a negatively charged first plate can be calculated using the formula C = Q/V, where Q is the charge on the plate and V is the potential difference between the two plates.

5. What are some practical applications of capacitors with a negatively charged first plate?

Capacitors with a negatively charged first plate are commonly used in electronic circuits, such as filters, oscillators, and power supplies. They are also used in energy storage devices, such as batteries and electric vehicles.

Similar threads

Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
11
Views
1K
Replies
2
Views
2K
Replies
14
Views
2K
Replies
101
Views
7K
Replies
7
Views
1K
  • Electromagnetism
Replies
16
Views
699
Replies
13
Views
2K
Replies
14
Views
2K
  • Electromagnetism
Replies
20
Views
8K
Back
Top