Capacitance: (multiple choice)

[predentalgirl1]

A capacitor is first connected to a 6.0 V battery and then disconnected and connected to a 12.0 V battery. How does the charge on one of its plates change: (a) It increases, (b) it decreases, or (c) it 1stays the same?








(c) (because the charge on the plate is
depending upon the area of the surface of the plate)

Right?? Not right?

 

[mjsd]

Q=CV
but one thing is not clear, because polarity matters

 

[predentalgirl1]

Now I think it's A) increases...Is this right

 

[mjsd]

several assumptions would have to be made, but A) seems the most logical for this question... unless it is part of a bigger problem which tells you more about the setup.