- #1
phys-lexic
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1. To make a parallel plate capacitor, you have available two flat plates of aluminum (area = 190 cm2), a sheet of paper (thickness = 0.10 mm, κ = 3.5), a sheet of glass (thickness = 2.0 mm, κ. = 7.0), and a slab of paraffin (thickness = 10.0 mm, κ = 2.0). Find each's capacitance; then enter the largest capacitance possible, of the three, in nF and the smallest in pF.
2. (capacitance) = ((epsilon not)x(Area)x(k)) / (d)
**d, or distance between the capacitors, would be the thickness of the paper/glass/paraffin right?**
3. my answers are:
5.885E-7 farads for paper
5.885E-8 farads for glass
3.363E-9 farads for paraffin
-smallest = 3363 pF (paraffin)
-largest = 588.5 nF (paper)
when i enter the values on my webassign it says I am wrong... are the values correct and just converted wrong or am i totally off [i did converted all the given values to meters before plugging them into the equation]
2. (capacitance) = ((epsilon not)x(Area)x(k)) / (d)
**d, or distance between the capacitors, would be the thickness of the paper/glass/paraffin right?**
3. my answers are:
5.885E-7 farads for paper
5.885E-8 farads for glass
3.363E-9 farads for paraffin
-smallest = 3363 pF (paraffin)
-largest = 588.5 nF (paper)
when i enter the values on my webassign it says I am wrong... are the values correct and just converted wrong or am i totally off [i did converted all the given values to meters before plugging them into the equation]