Can You Use Logarithmic Differentiation to Solve for a Base 2 Function?

[huan.conchito]

Can someone please differentiate this [itex] \!\(Log\\_2\[[x^3 + 1][/itex]
im stuck because its base 2

 

[Moo Of Doom]

Remember that [tex]\log_a{x}=\frac{\log_b{x}}{\log_b{a}}[/tex]

 

[huan.conchito]

so is this my next step? and then do i use quotient rule?
[tex]\log_2{(x^3+1)}=\frac{\ln{(x^3+1)}}{\ln{2}}[/tex]

 

[Moo Of Doom]

You don't need the quotient rule because ln2 is a constant.

 

[huan.conchito]

so is the the answer then?
[itex]3x^2/(x^3+1)[/itex]

 

[Hurkyl]

He used the chain rule just fine.

He just forgot how to deal with a constant multiple. Hint: what's the derivative of 6 x^2?

 

[huan.conchito]

ah, thanks
[itex]3x^2/(x^3+1)Ln2[/itex]

 

[dextercioby]

And [itex] \ln 2[/itex] should be there somewhere.In the denominator,to be precise.

And the thread title,to be accurate,should have been "logarithm('s) derivative"...

Daniel.

 

[SpaceTiger]

He used the chain rule just fine.

I deleted my response because he changed his post before I submitted, or it displayed incorrectly on my browser.