- #1
matrix_204
- 101
- 0
I am having great, great difficulties in solving this problem, its asking me to find a function that is continuous everywhere which takes each of its values exactly 3 times(like give an example of a function, no proving). This part, i have a little imagination of my own to start, but the second part is the hardest one, which i can't even think about.
It says to prove that there is no such function if there are two values instead of three.
It says to prove that there is no such function if there are two values instead of three.