- #1
- 6,223
- 31
If I have a matrix
[tex]
A= \left(
\begin{array}{ccc}
1 & 2 & 3\\
0 & -1 & 4\\
1 & 1 & 6
\end{array}
\right)
[/tex]
and I need to find [itex]A^{-1}[/itex] I would just augment with the identity matrix and then do row operations. But if I want to use column operations instead does it work in the same manner? because I think if use the column operations, the matrix A would be reduced to RRE form but nothing will happen to the identity matrix.
(Not too sure if I was clear about my problem.)
[tex]
A= \left(
\begin{array}{ccc}
1 & 2 & 3\\
0 & -1 & 4\\
1 & 1 & 6
\end{array}
\right)
[/tex]
and I need to find [itex]A^{-1}[/itex] I would just augment with the identity matrix and then do row operations. But if I want to use column operations instead does it work in the same manner? because I think if use the column operations, the matrix A would be reduced to RRE form but nothing will happen to the identity matrix.
(Not too sure if I was clear about my problem.)