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- Thread starter dwsmith
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- Jan 26, 2012

- 236

I think you want to rephrase it as, "What geometric surface encloses the maximum volume with a given surface area". In other words, you have 1 unit-squared of material and you want to enclose a surface to yields maximum volume.How do I set up the following problem?

What geometric surface encloses the maximum volume with the minimum surface area?

Let $\Omega$ be bounded region in $\mathbb{R}^3$. You want to maximize,

$$ \iiint_\Omega 1 $$

Given the condition that,

$$ \iint_{\partial \Omega} 1 ~ ds = 1 $$

If we care about small details this question is a lot more complicated to phrase. Then we need to restrict ourselves to measurable sets such that .. blah blah blah.

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Here is another way to phrase it: Suppose $\Omega$ is a bounded (measurable) region in space with $\partial \Omega$ (boundary of $\Omega$) being a surface. Then,

$$ \text{Volume}(\Omega) \leq \frac{1}{6\sqrt{\pi}} \text{Area}(\partial \Omega)^{3/2} $$

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I don't think I want to rephrase it. The question is number 13 hereI think you want to rephrase it as, "What geometric surface encloses the maximum volume with a given surface area". In other words, you have 1 unit-squared of material and you want to enclose a surface to yields maximum volume.

Let $\Omega$ be bounded region in $\mathbb{R}^3$. You want to maximize,

$$ \iiint_\Omega 1 $$

Given the condition that,

$$ \iint_{\partial \Omega} 1 ~ ds = 1 $$

If we care about small details this question is a lot more complicated to phrase. Then we need to restrict ourselves to measurable sets such that .. blah blah blah.

- Jan 29, 2012

- 1,151

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- #5

Then how would I show a sphere is the smallest surface containing a given volume?givenvolume is a sphere and that the largest area for agivensize surface is a sphere.

- Feb 15, 2012

- 1,967

The "best" answer that isn't too complicated I can think of is: soap bubbles are smarter than us, and they form spherical shells under such constraints.