Calculation of some electron properties

In summary, the conversation involves calculating various values related to an electron with a total energy of 5000MeV before a collision. The equations and attempts at solutions are discussed, and the correct values are found for the mass energy, Lorentz factor, speed as a fraction of c, and momentum.
  • #1
Lissajoux
82
0

Homework Statement



An electron has a total energy of exactly [itex]5000MeV[/itex] just before a collision.

I need to calculate:

1. The mass energy in [itex]MeV[/itex]

2. The Lorentz factor [itex]\gamma[/itex]

3. The speed as a fraction of [itex]c[/itex]

4. The momentum in [itex]MeV/c^{2}[/itex]

Homework Equations



Within the problem statement and solution attempt.

The Attempt at a Solution



These seemed pretty easy, but I'm for some reason finding issues with them at the moment now I've got round to trying to do the calculations.

This is what I have so far:

1.

[tex]m_{e}=9.10938215\times 10^{-31}~\textrm{kg}[/tex]

Use formula:

[tex]E=m_{e}c^{2}[/tex]

Hence:

[tex]E=8.198444\times 10^{-14}~\textrm{J}=0.511763~\textrm{MeV}[/tex]

So that's the mass energy of the electron.

Not sure if was meant to use [itex]E=5000~\textrm{MeV}[/itex] instead? and whether that equation should have a [itex]\gamma[/itex] in it?

2.

The lorentz factor is given by:

[tex]\gamma=\frac{1}{\sqrt{1-\left(\frac{v}{c}\right)^{2}}}}[/tex]

But I don't know [itex]v_{e}[/itex]

So I thought could use this:

[tex]E=m_{e}\gamma c^{2}\implies \gamma= \frac{E}{m_{e}c^{2}}[/tex]

But that doesn't seem to work.

3.

Thought I could use:

[tex]E=\frac{1}{2}m_{e]c^{2}[/tex]

But I believe I need to account for a [itex]\gamma[/itex] in there, and I can't get it to work. Maybe I'm using the wrong energy.

4.

Momentum given by:

[tex]P=m_{e}v_{e}[/tex]

.. again need a [itex]\gamma[/itex] in there?

- - - - - - - - -

I don't think I'm too far off the answers, just need a bit of advice. :smile:
 
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  • #2
1 is correct (mass energy typically refers to rest mass energy)

For 2, the total energy is [itex]E = \gamma mc^2[/itex], so it's just [itex]5000/0.511...[/itex].

Now that you know [itex]\gamma[/itex], the rest should follow.
 
  • #3
Yeah think I've figured it out now :smile:
 

Related to Calculation of some electron properties

1. What are some of the electron properties that can be calculated?

Some of the electron properties that can be calculated include the energy levels, orbital shapes, spin, and magnetic moment.

2. How are these electron properties calculated?

These electron properties are calculated using mathematical equations and models, such as the Schrödinger equation, which takes into account the electron's mass, charge, and position.

3. Why is it important to calculate electron properties?

Calculating electron properties allows us to better understand the behavior and interactions of electrons, which are the building blocks of matter. This knowledge is crucial in fields such as chemistry, physics, and materials science.

4. What tools or techniques are used in the calculation of electron properties?

Some common tools and techniques used in the calculation of electron properties include quantum mechanical models, computational programs, and spectroscopic methods.

5. Are there any real-world applications for the calculation of electron properties?

Yes, there are several real-world applications for the calculation of electron properties. For example, it is used in the development of new materials with specific electronic properties, in understanding the electronic structure of molecules in drug design, and in the design of electronic devices such as transistors and solar cells.

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