- #1
The3vilburrit0
- 1
- 0
Homework Statement
In a project in a summer engineering class I'm taking, I have been tasked with finding Young's Modulus with three different diameters of spaghetti: Thin (1.41 mm), Normal (1.73 mm), and Thick (1.89 mm). Although this is my first time ever attempting to try engineering without taking Calculus 1 or Physics, but I've managed to get as far as finding the stress values. The values are a result from a bending test that has multiple lengths of exposed spaghetti in the middle. In essence, there are three types of support ledges with each support ledge being a different length apart from the pair on the other side of the contraption. The values that I've recorded from testing are below. I tried creating a table using all that I could, but it didn't turn out like I would've liked it to.
THIN (1.41 mm)
Weight Held @ 75 mm : DIDN'T HAVE TO TESTWeight Held @ 95 mm : DIDN'T HAVE TO TEST
Weight Held @ 117 mm : 40 g with 16 mm deflection
NORMAL (1.73 mm)
Weight Held @ 75 mm : 113 g with 7 mm deflectionWeight Held @ 95 mm : 74 g with 10 mm deflection
Weight Held @ 117 mm : 62 g with 14 mm deflection
THIN (1.41 mm)
Weight Held @ 75 mm : DIDN'T HAVE TO TESTWeight Held @ 95 mm : DIDN'T HAVE TO TEST
Weight Held @ 117 mm : 85 g with 13 mm deflection
Homework Equations
First off, is it even possible to substitute the deformation to find strain with the deflection? Also, once I find Young's Modulus, is that number the slope throughout the elastic deformation time span?
The Attempt at a Solution
Using the area of a circle (A=∏r2), I've been able to find the cross-sectional area of the different thicknesses of the spaghetti. For Thin, the area is 1.561 mm2. For Normal, the area is 2.351 mm2. Lastly for Thick, the area is 2.806 mm2.
I then converted each weight that the types of spaghetti held from grams to kilograms, and then multiplied by 9.81 to convert it into Newtons. Thin: .251 (117 mm); Normal: 1.108 (75 mm), .726 (95 mm), .608 (117 mm); and .883 (117 mm) for Thick. Using the stress formula (σ= force/area), I found the following: Thin: .251 (117 mm); Normal: .471 (75 mm), .309 (95 mm), .259 (117 mm); and .296 (117 mm) for Thick.
To solve the rest of Young's Modulus to find the slope of the Elastic Deformation time span, I need to find what strain is, but to find strain, I also need to know what E (Young's Modulus) is. So pretty much in order to find one thing, I need to know the other and it just keeps going in a continuous loop.
Thank you very much for helping!
-Chris
Last edited: