- #1
Jacob87411
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A 1470 kg automobile has a wheel base (the distance between the axles) of 2.70 m. The center of mass of the automobile is on the center line at a point 1.20 m behind the front axle. Find the force exerted by the ground on each wheel.
A bit confused here. Were going to use the sum of the torque = 0, using the center of mass (1.2m behind the front axle and 1.5m infront of the back) as our starting point. We need to find the force in kN on each wheel. So between the 4 wheels they must support 14,406 N (1470*9.8), i know this much but am confused where to go from here
A bit confused here. Were going to use the sum of the torque = 0, using the center of mass (1.2m behind the front axle and 1.5m infront of the back) as our starting point. We need to find the force in kN on each wheel. So between the 4 wheels they must support 14,406 N (1470*9.8), i know this much but am confused where to go from here