- #1
elementozzy
- 8
- 0
So I got a warning for just posting questions so I'll do as best as I can to try and put effort lol
A Young's interference experiment is performed with monochromatic light. The separation between the slits, d, is .50 mm, and the interference
pattern on a screen L = 3.3 m away shows the first maximum y1 = 3.4 mm from the center of the pattern. What is the wavelength?
GIVEN DATA
d=.50mm
L=3.3m
y1= 3.4mm
Yn=(nλL)/d
I need to know if I'm attempting this right.
I started off by plugging in y1=3.4mm, L=3.3m and d=.50mm
Pretty simple.
3.4=(nλ3.3)/.5
1.7=(nλ3.3)
.5151...=λ
?
Am I right by plugging in 1 for n?
Homework Statement
A Young's interference experiment is performed with monochromatic light. The separation between the slits, d, is .50 mm, and the interference
pattern on a screen L = 3.3 m away shows the first maximum y1 = 3.4 mm from the center of the pattern. What is the wavelength?
GIVEN DATA
d=.50mm
L=3.3m
y1= 3.4mm
Homework Equations
Yn=(nλL)/d
The Attempt at a Solution
I need to know if I'm attempting this right.
I started off by plugging in y1=3.4mm, L=3.3m and d=.50mm
Pretty simple.
3.4=(nλ3.3)/.5
1.7=(nλ3.3)
.5151...=λ
?
Am I right by plugging in 1 for n?