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Cglez1280
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Homework Statement
A box of mass 6.2 kg slides 4.8 m down a ramp that is inclined 38 degrees to the horizontal. What is the velocity of the box right before it hits the ground?
Mass=6.2 Height=dsintheta? V=is what needs to be found theta=38
Homework Equations
GPE=mgh=mgdsin(theta)
KE=1/2mv^2
New equation:
GPE⋅+KE⋅=GPE
mgh⋅+1/2mv^2=mgh
1/2mv^2=mgh-mgh⋅
mv^2=2(mgh-mgh⋅)
V^2=2(mgh-mgh⋅)/m
v=√2(mgh-mgh⋅)/m
The Attempt at a Solution
i just want to see if my equations are correct. if it could be factored even more could someone tell me. like the two mgh's i feel like could be changed but I am not too sure. I know h is also h=dsin(θ) but would it be the same for the two since it will be different?
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