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rebc
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Homework Statement
I am to calculate the density of a nucleus, say, of Iron, with mass 55.845 amu.
Homework Equations
see below
The Attempt at a Solution
I come to notice that all elements have the same value for the volume if I use the formula:
$$mass=m=m_{amu}(1.66\times10^{-27}kg/1u)$$
$$volume=V=\frac{4}{3}\pi r^3$$
$$
radius=R=r_0 A^{1/3}, \ r_0=1.25\times 10^{-15}m
$$
$$density=\rho = \frac{m}{V} = \frac{A(1.66\times 10^{-27})}{4/3\pi r_0^3A}=\frac{(1.66\times 10^{-27})}{4/3\pi r_0^3}=constant?$$
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