- #1
dimensionless
- 462
- 1
Why doesn't this force give the gravitational acceleration on the surface of the earth?
[tex]a = G \cdot \frac{m}{r^2}[/tex]
I would think that it could be derived from the law of universal gravitation:
[tex]F = G \cdot \frac{m_1 \cdot m_2}{r^2}[/tex]
Since [tex]F = m_2 a[/tex]
[tex]a = G \cdot \frac{m}{r^2}[/tex]
I would think that it could be derived from the law of universal gravitation:
[tex]F = G \cdot \frac{m_1 \cdot m_2}{r^2}[/tex]
Since [tex]F = m_2 a[/tex]