Calculating Tension For A Massless String

In summary, the tension on the rope will be the same whether the gymnast is hanging motionless or climbing at a constant rate, as long as there is no acceleration and the gravitational force does not depend on height. This can be shown using momentum conservation.
  • #1
Yosty22
185
4

Homework Statement


A gymnast of mass 59.0kg hangs from a vertical rope attached to the ceiling. You can ignore the weight of the rope and assume that the rope does not stretch. Use 9.81 m/s^2 for the value for the acceleration of gravity.
Calculate the Tension, T, in the rope if the gymnast climbs the rope at a constant rate.


Homework Equations



None (that I can think of)

The Attempt at a Solution



Since the rope is massless, I was thinking that the tension on the rope if she hangs there motionless should be the same as if she is climbing it. Solving for the Tension of the rope while she was sitting there, I just used mass times gravity, in this case; 59kg*9.81m/s^2=578.79N. Would this answer be the same if she was climbing up the rope as well?
Thanks a lot in advance.
 
Physics news on Phys.org
  • #2
Since the rope is massless, I was thinking that the tension on the rope if she hangs there motionless should be the same as if she is climbing it.
Right, but that is true for a massive rope as well.
Would this answer be the same if she was climbing up the rope as well?
Yes. You can use momentum conservation to show this, for example.
 
  • #3
mfb said:
Right, but that is true for a massive rope as well.

This is true as long there is no acceleration, correct? As long as the velocity is constant, that is always true?
 
  • #4
Yes - if we assume that the gravitational force does not depend on the height (a very good approximation here...).
 
  • #5


Yes, your approach is correct. The tension in the rope while the gymnast is hanging motionless is equal to her weight (mg), which in this case is 578.79N. This is because the rope is massless and therefore does not contribute any additional weight or tension.

When the gymnast starts climbing the rope at a constant rate, the tension in the rope will increase to support her weight as well as the additional force she is exerting to climb. This tension can be calculated using the same formula, T=mg, where m is the mass of the gymnast and g is the acceleration due to gravity.

So in this case, the tension in the rope while the gymnast is climbing at a constant rate would be 59kg*9.81m/s^2 = 578.79N + force exerted by the gymnast to climb.

Hope this helps!
 

Related to Calculating Tension For A Massless String

What is tension?

Tension is a force that is experienced by a string or rope when it is pulled tight by opposing forces.

Why is it important to calculate tension for a massless string?

It is important to calculate tension for a massless string because it helps us understand the behavior and limitations of the string in different situations, and allows us to make accurate predictions and calculations in physics and engineering problems.

How do you calculate tension for a massless string?

Tension for a massless string can be calculated using the equation T = F/a, where T is the tension, F is the force applied to the string, and a is the acceleration of the string.

What factors affect the tension of a massless string?

The tension of a massless string is affected by the magnitude and direction of the forces acting on the string, as well as the length and stiffness of the string.

Can the tension of a massless string ever be greater than the applied force?

No, the tension of a massless string can never be greater than the applied force. This is because a massless string cannot support any weight or mass, so all the force applied to the string is transferred through it without any loss.

Similar threads

  • Introductory Physics Homework Help
Replies
13
Views
2K
  • Introductory Physics Homework Help
Replies
5
Views
7K
  • Introductory Physics Homework Help
Replies
6
Views
6K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
6
Views
3K
  • Introductory Physics Homework Help
Replies
8
Views
6K
  • Introductory Physics Homework Help
Replies
2
Views
2K
  • Introductory Physics Homework Help
Replies
32
Views
10K
  • Introductory Physics Homework Help
Replies
5
Views
1K
  • Introductory Physics Homework Help
Replies
19
Views
3K
Back
Top