For one thing, you only calculated the inward force exerted by the air outside the house. As ice109 says, you forgot that it's the air inside the house that pushes the walls outward. (Find the net force.)kiwikahuna said:I converted 0.2 atm to 20260 Pa. The area is 11m X 16 m = 176 m^2.
F = (20260 Pa) (176 m^2)
F = 3.56576 X 10^6 N
The answer is wrong. What did I overlook?
kiwikahuna said:The problem doesn't say.
Doc Al said:For one thing, you only calculated the inward force exerted by the air outside the house. As ice109 says, you forgot that it's the air inside the house that pushes the walls outward. (Find the net force.)
The outward force of a tornado on a wall is calculated using the formula F = ρ * V^2 * A, where F is the force, ρ is the air density, V is the wind speed, and A is the area of the wall.
The outward force of a tornado on a wall is influenced by the air density, wind speed, and the size and shape of the wall. Other factors such as the strength and intensity of the tornado may also play a role.
Yes, the outward force of a tornado on a wall can cause significant structural damage, especially if the wall is not properly reinforced or designed to withstand extreme weather conditions.
The best way to mitigate the outward force of a tornado on a wall is to reinforce the wall with sturdy materials and proper construction techniques. Building codes and regulations also play a crucial role in ensuring the structural integrity of buildings in tornado-prone areas.
While it is not possible to predict the exact outward force of a tornado on a wall, meteorologists and scientists can estimate the force based on the strength and intensity of the tornado, as well as the size and shape of the wall in its path.