Calculating Nonconservative Energy Loss in Pumped-Storage Reservoirs

In summary, the problem involves a pumped-storage reservoir with a height of 136 m above its generating station and a water capacity of 9.0×10^9 kg. The power plant generates 346 MW of electric power over a period of 6.9 h. The question is asking for the fraction of initial potential energy lost to nonconservative forces, which would not be converted into electricity.
  • #1
BMW25
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new problem!

A pumped-storage reservoir sits 136 m above its generating station and holds 9.0×10^9 kg of water. The power plant generates 346 MW of electric power while draining the reservoir over an 6.9 h period.
What fraction of the initial potential energy is lost to nonconservative forces (i.e., does not emerge as electricity)?

could you please guys help me with that? I gave up with that
I need that in hour guys please please.
 
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  • #2
136 m above its generating station and holds 9.0×10^9 kg. so what is the gravitational potential energy?

346 MW over an 6.9 h... what is the energy generated here?

so how much energy is lost?

what is the fraction of this energy to the original gravitational potential energy.
 
  • #3


I would approach this problem by first understanding the concept of nonconservative energy loss in pumped-storage reservoirs. This refers to the energy that is lost during the process of converting potential energy (stored in the water at a higher elevation) into electrical energy. This loss can be caused by various factors such as friction, turbulence, and inefficiencies in the system.

To calculate the nonconservative energy loss in this specific scenario, we can use the equation:

Nonconservative energy loss = Initial potential energy - Final electrical energy output

Since we are given the initial potential energy (9.0×10^9 kg x 136 m x 9.8 m/s^2 = 1.21×10^13 J) and the electrical energy output (346 MW x 6.9 h x 3600 s/h = 8.48×10^11 J), we can calculate the nonconservative energy loss as:

Nonconservative energy loss = 1.21×10^13 J - 8.48×10^11 J = 1.13×10^13 J

To determine the fraction of the initial potential energy lost to nonconservative forces, we can divide the nonconservative energy loss by the initial potential energy:

Fraction of initial potential energy lost = (1.13×10^13 J / 1.21×10^13 J) = 0.93 or 93%

This means that 93% of the initial potential energy is lost to nonconservative forces and only 7% is converted into electrical energy. This high percentage of energy loss highlights the importance of continuously improving and optimizing the design and operation of pumped-storage reservoirs to minimize nonconservative energy loss and increase overall efficiency.
 

Related to Calculating Nonconservative Energy Loss in Pumped-Storage Reservoirs

1. What is a pumped-storage reservoir?

A pumped-storage reservoir is a type of energy storage system that uses two bodies of water at different elevations to store and release energy. During periods of low energy demand, water is pumped from a lower reservoir to a higher one. When energy demand is high, the water is released back to the lower reservoir, passing through a turbine to generate electricity.

2. How is nonconservative energy loss calculated in pumped-storage reservoirs?

Nonconservative energy loss in pumped-storage reservoirs is typically calculated using the head-loss method, which takes into account the difference in elevation between the two reservoirs, the flow rate, and the efficiency of the pumping and turbine equipment.

3. What factors contribute to nonconservative energy loss in pumped-storage reservoirs?

The main factors that contribute to nonconservative energy loss in pumped-storage reservoirs include frictional losses due to water flow, losses in the pumping and turbine equipment, and losses due to water turbulence and mixing in the reservoirs.

4. How can nonconservative energy loss be minimized in pumped-storage reservoirs?

To minimize nonconservative energy loss in pumped-storage reservoirs, engineers can design the system to minimize frictional losses by using larger pipes and smoother materials, optimize the efficiency of the pumping and turbine equipment, and reduce water turbulence and mixing in the reservoirs through proper design and operation.

5. Why is it important to calculate nonconservative energy loss in pumped-storage reservoirs?

Calculating nonconservative energy loss in pumped-storage reservoirs is important for accurately assessing the efficiency and performance of the system. It also helps in identifying potential areas for improvement and optimizing the design and operation of the system to reduce energy loss and increase overall efficiency.

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