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Look at the pulleys and the position of the rope.anigeo said:
because that is the answer and that's troubling me.could you say that it is incorrect?Doc Al said:
No, it's correct. Assuming there's no friction between m1 and m2, the net force on m2 will be zero. See Low-Q's post for details.anigeo said:
To calculate net force on mass m2, you need to consider the individual forces acting on the mass and their direction. Then, you can use the formula Fnet = ma, where Fnet represents the net force, m represents the mass, and a represents the acceleration. This will give you the net force acting on mass m2.
Net force is the overall force acting on an object, taking into account all the individual forces acting on it. Individual forces, on the other hand, are the specific forces acting on the object, such as gravity, friction, or applied forces. Net force is the sum of all the individual forces.
The direction of net force is determined by the direction of the individual forces acting on the object. If the forces are acting in the same direction, the net force will also be in that direction. If the forces are acting in opposite directions, the net force will be in the direction of the stronger force.
Yes, net force can be negative. This would happen if the individual forces acting on the object are in opposite directions and the stronger force is in the negative direction. Negative net force means that the overall force is acting in the opposite direction of the object's motion or intended motion.
The mass of an object has a direct relationship with net force. The greater the mass, the greater the net force needed to accelerate the object. This is reflected in the formula Fnet = ma, where a is the acceleration and is directly proportional to the mass. In simpler terms, the more massive an object is, the more force is needed to move it.
