Calculating Maximum Compression and Acceleration in a Car-Spring Collision

In summary, the car moves across a level surface and collides with a spring-loaded guard rail. The spring has a spring constant of 2.0E6N/m. If the spring is compressed by only 0.30-m, the change in the mechanical energy due to friction is 8.0E5N.
  • #1
ellyb
7
0
A 1300-kg car starts at rest and rolls down a hill from a height of 10.0-m. It moves across a level surface and collides with a spring-loaded guard rail designed to bring the car safely to a stop. The spring has a spring constant of 2.0E6N/m.
Neglecting any losses due to friction, and ignoring the rotational kinetic energy of the wheels, find the maximum distance the spring is compressed.

Calculate the maximum acceleration of the car after contact with the spring (again ignore brakes, friction, etc.). Comment on the possibility of injury to the driver.

If the spring is compressed by only 0.30-m, find the change in the mechanical energy due to friction.

*I am really not sure where to start with this quesion can someone please help me?
 
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  • #2
[tex]E_o = E_f[/tex]
That will get you the first part
 
  • #3
First you should be asking yourself, "what is going on?". You have an object starting from rest at a certain height, and then it proceeds downward toward a flat surface. Energy is needed to make the object move. Where does this energy come from? Is energy conserved? And finally, What happens to this energy as the object moves down the hill and compresses the spring?

As for the second part, you are analyzing the part where the car is traveling on the flat surface, and then continues to compress the spring. You can solve this part using F = ma. What forces are acting on the car? We know a spring force is acting on it.. when is this spring force maximum?
 
  • #4
[tex] E_o = E_f [/tex]
[tex] mgh = \frac {1}{2} k x^2[/tex]
I don't know why you have mgx in the second part. The car is moving horizontally once it hits the spring.
 
  • #5
oh right...so it would be
x= squar(127400(2)/2.0E6)=.4 m
 
Last edited:
  • #6
You messed up on your calculations.
 
  • #7
How do i find the maximum acceleration?
 
  • #8
F = -kx = ma
 
  • #9
Is this right?
f=-kx=-2.0E6*0.4=8.0E5N
a=F/m=8.0E5N/1300Kg=615.4 kg.n
 
  • #10
If the spring is compressed by only 0.30-m, find the change in the mechanical energy due to friction.
How do i find this part?
 
  • #11
KE= 1/2 2.0E6 N/m * (.3)^2
Is this the right formula to use for the mechanical energy last part?
 

Related to Calculating Maximum Compression and Acceleration in a Car-Spring Collision

1. What is the definition of spring constant in physics?

In physics, spring constant is a measure of the stiffness of a spring. It is defined as the force required to stretch or compress a spring by a unit length. It is typically denoted by the letter k and has units of newtons per meter (N/m).

2. How is spring constant calculated?

Spring constant can be calculated by dividing the applied force by the displacement of the spring. This is known as Hooke's Law, which states that the force applied to a spring is directly proportional to the amount of stretch or compression of the spring.

3. What factors affect the spring constant?

The spring constant of a spring can be affected by several factors, including the material of the spring, its length, diameter, and number of coils. Additionally, the temperature and the applied force can also impact the spring constant.

4. What are the units of spring constant?

Spring constant is measured in newtons per meter (N/m) in the SI system of units. In the cgs system, it is measured in dynes per centimeter (dyn/cm).

5. How does spring constant relate to the stiffness of a spring?

Spring constant is a measure of the stiffness of a spring. A higher spring constant indicates a stiffer spring, meaning that it will require more force to stretch or compress the spring by a certain length. In contrast, a lower spring constant indicates a less stiff spring, which will require less force to deform it.

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