ColdRifle said:m1u1=m2u2 Since we want the ratio of m1 and m2 we make m2=m1*k(a constant)
m1(9m/s)=m1*k*5m/s
k=9/5 So the ratio of the two masses is that the 1st has the 5/9 of the seconds mass
The mass of a disc can be calculated using the formula M = (Vexp2 * R) / (2 * G), where Vexp is the explosion velocity, R is the radius of the disc, and G is the gravitational constant.
The explosion velocity should be in units of meters per second (m/s) and the disc radius should be in units of meters (m) for the mass calculation to be accurate.
Yes, this calculation can be applied to any type of disc explosion as long as the explosion velocity and disc radius are known. However, the accuracy of the result may vary depending on the specific circumstances of the explosion.
This method assumes that the explosion velocity is solely due to the mass of the disc and that the disc is uniform in density. It also assumes that the gravitational force is the only force acting on the disc.
Calculating the mass of a disc from an explosion velocity can provide valuable information about the composition and structure of the disc. This can be useful in various fields such as astrophysics, geology, and materials science.