- #1
GrandMaster87
- 18
- 0
Homework Statement
A mountain climber stands at the top of a 50m cliff that overhangs a calm pool. She throws two stones vertically download 1s apart and observe that the two stones reach the water simultaneously after a while. The first stone was thrown at an initial speed of 2m[tex]^{-1}[/tex].s
Calculate the initial speed at which she threw the second stone. Ignore the effects of friction
Homework Equations
The Attempt at a Solution
Vf[tex]^{2}[/tex]=V[tex]_{i}[/tex][tex]^{2}[/tex] + a[tex]\Delta[/tex]y
=2(2)[tex]^{2}[/tex]=2(9.8)(50)=31.37
Vf=5.6m.s[tex]^{-1}[/tex]
V[tex]_{f}[/tex]=v[tex]_{i}[/tex]+at
5.6=2+9.8t
t=0.367...
t=0.37s
I am not sure if I am right...because now i have to -1 second from the t above hence giving me a negative second to enter in a formula to find the initial velocity of the stone...
Can someone help me...the model answer gives me an anser of 15.2m/s downwards...how can that be? surely it is wrong