- #1
Tanya Back
- 18
- 0
Hey
I am having trouble doing this question-->
A gardener exerts a force of 150 N [ 22 degrees below the horizontal] in pushing a large 18 Kg box a distance of 1.6 m. The coefficient of kinetic friction between the box and the floor is 0.55.
Question -->
Use Newton's law to determine magnitudes of the normal force and force of friction on the box?
Solution :
Fn= Fag perpendicular
= Fgcosa
= (9.8)(18)cos22
= 164 N
Ff= uFn
=0.55(164)
= 89.9 N
***********
My answers are wrong becasue the answer is suppose to be Fn = 230 N and Ff= 130 N
What did i do wrong? how can i fix it?
I am having trouble doing this question-->
A gardener exerts a force of 150 N [ 22 degrees below the horizontal] in pushing a large 18 Kg box a distance of 1.6 m. The coefficient of kinetic friction between the box and the floor is 0.55.
Question -->
Use Newton's law to determine magnitudes of the normal force and force of friction on the box?
Solution :
Fn= Fag perpendicular
= Fgcosa
= (9.8)(18)cos22
= 164 N
Ff= uFn
=0.55(164)
= 89.9 N
***********
My answers are wrong becasue the answer is suppose to be Fn = 230 N and Ff= 130 N
What did i do wrong? how can i fix it?