- #1
some bloke
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- TL;DR Summary
- I need to work out the equations to determine the load capacity needed for a beam to catch a falling weight.
I am designing a machine at the moment, and I am struggling to get my head around impact forces. I have established that the force applied is mgh/d, but I am struggling to work out the value for d.
Taking it in isolation, assuming that the falling weight does not "give" in any significant way when it lands on the end of the beam, then the value for "d" is going to be the amount of flex that the beam experiences, but this in turn is related to the force, which is related to the distance, and I'm going in circles.
I want, ideally, as little "d" as possible - a solid landing, as it were, akin to the weight landing on a concrete pavement. But, if I plug "d" in as 0, we get infinite force, so I'm coming up stumped again.
Current values I'm using to try and work this out are:
m=125kg
g=9.81ms-2
h=1m
Beam can be treated as cylindrical, 0.5m long and made of steel, fixed rigidly at one end and the weight is caught a the other, after falling 1m.
Beam diameter is going to depend on the force (which depends on the distance, which depends on the flex, which depends on the beam diameter ow my head)
The premise is similar to someone jumping on a diving board.
Please can someone help me to tie this together!
Taking it in isolation, assuming that the falling weight does not "give" in any significant way when it lands on the end of the beam, then the value for "d" is going to be the amount of flex that the beam experiences, but this in turn is related to the force, which is related to the distance, and I'm going in circles.
I want, ideally, as little "d" as possible - a solid landing, as it were, akin to the weight landing on a concrete pavement. But, if I plug "d" in as 0, we get infinite force, so I'm coming up stumped again.
Current values I'm using to try and work this out are:
m=125kg
g=9.81ms-2
h=1m
Beam can be treated as cylindrical, 0.5m long and made of steel, fixed rigidly at one end and the weight is caught a the other, after falling 1m.
Beam diameter is going to depend on the force (which depends on the distance, which depends on the flex, which depends on the beam diameter ow my head)
The premise is similar to someone jumping on a diving board.
Please can someone help me to tie this together!