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roy_ament
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I'm new in this forum, so i don't know if this is in the correct place..
I got 3 charges
q1= 2.0x10^-6C
q2=8.0x10^-6C
Q=4.0x10^-6C
They're placed in the corners of a triangle like in this draw
I have to know the force that q1 and q2 act on Q, the magnitude, and the direction
F=(kq1q2)/r2
for the angle which is 38.65 i do the tan-1 of .40/.50
Fq1Q=( (9x109 Nm2/c2) (2.0x10-6 C) (4.0x10-6C))/(.50m)2
Fq1Q= .288N
So know i split in the components of X and Y right?
x= .288(cos38.65) Y= .288 (sin38.65)
x=.22N Y= .1798
Fq2Q=( (9x109 Nm2/c2) (8.0x10-6 C) (4.0x10-6C))/(.50m)2
Fq2Q= 1.152N
x=1.152 (cos 38.65) Y=1.152 (sin38.65)
x=.8999n y=.7119n
Now for the magnitude
x= .22+.899=1.119N
y=-.1798+.7119= .5321N
sqrt((1.119)2(.5321)2)= 1.311N
as for the direction
tan-1 = (.5321/1.119)= 25.43°so.. am I right?
all sugetionts are really apreciated, tips and stuff.. hope anyone can help me
sry if my descriptions are wrong, I'm from mexico and my english is not perfect:shy:
if someone also could give me other exercises for practice... it will be perfect!
Homework Statement
I got 3 charges
q1= 2.0x10^-6C
q2=8.0x10^-6C
Q=4.0x10^-6C
They're placed in the corners of a triangle like in this draw
I have to know the force that q1 and q2 act on Q, the magnitude, and the direction
Homework Equations
F=(kq1q2)/r2
for the angle which is 38.65 i do the tan-1 of .40/.50
The Attempt at a Solution
Fq1Q=( (9x109 Nm2/c2) (2.0x10-6 C) (4.0x10-6C))/(.50m)2
Fq1Q= .288N
So know i split in the components of X and Y right?
x= .288(cos38.65) Y= .288 (sin38.65)
x=.22N Y= .1798
Fq2Q=( (9x109 Nm2/c2) (8.0x10-6 C) (4.0x10-6C))/(.50m)2
Fq2Q= 1.152N
x=1.152 (cos 38.65) Y=1.152 (sin38.65)
x=.8999n y=.7119n
Now for the magnitude
x= .22+.899=1.119N
y=-.1798+.7119= .5321N
sqrt((1.119)2(.5321)2)= 1.311N
as for the direction
tan-1 = (.5321/1.119)= 25.43°so.. am I right?
all sugetionts are really apreciated, tips and stuff.. hope anyone can help me
sry if my descriptions are wrong, I'm from mexico and my english is not perfect:shy:
if someone also could give me other exercises for practice... it will be perfect!
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