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killaI9BI
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Homework Statement
Another canoe question!
A canoe is headed directly across a river that is 200 m wide. Instead of moving with a constant velocity, the canoe moves with a constant acceleration of 4.0 x 10-2 m/s2. If the river is flowing with a constant velocity of 2.0 m/s, how long will it take for the canoe to reach the other side? How far down the river will it land? Sketch the shape of the path the canoe will follow.
Homework Equations
vf2 = vi2 + 2a X d
sin a/a = sin b/b
cos θ = Adjacent / Hypotenuse
The Attempt at a Solution
To calculate the velocity:
Vf2 = 0 + 2(0.04) X 200
Vf2 = 16m/s
and determine the angle:
sin Θ = (sin 90/16.12) x 2
Θ = 7.12°
I'm pretty sure I've messed something up at this point. My next step would be to try to figure out the distance of the hypotenuse in meters based on the angle that I calculated using CAH and the distance given (200m) which I think would be the adjacent side. I know something is wrong because the angle that I've calculated indicates the hypotenuse is shorter than the adjacent side of 200m.
Did I start out with the wrong velocity formula?
I appreciate any help you can provide!