- #1
steve321
- 25
- 0
this isn't really a problem, I'm trying to understand the table in this link:
http://www.nrc-cnrc.gc.ca/eng/ibp/irc/cbd/building-digest-36.html
basically it shows a wall assembly, it's 70 degrees on the inside, and it gives a list of the materials and their thicknesses in the wall
if we look at the gypsum plaster, we see it's conductivity (k) is 5 watts per meters kelvin, which i think means that for every square meter of this gypsum plaster, 5 watts of heat will pass through in an hour or something like that.
anyway the next column shows it's conductance, which i think just expresses the conductivity of that material in a certain thickness, so you divide by the thickness. the next column, resistance, is the opposite of conductance. but then i don't understand how they jump from there and conclude that the temperature is going through drop 4 degrees through the gypsum plaster. I'm not sure how they get there.
can anyone help explain this to me?
http://www.nrc-cnrc.gc.ca/eng/ibp/irc/cbd/building-digest-36.html
basically it shows a wall assembly, it's 70 degrees on the inside, and it gives a list of the materials and their thicknesses in the wall
if we look at the gypsum plaster, we see it's conductivity (k) is 5 watts per meters kelvin, which i think means that for every square meter of this gypsum plaster, 5 watts of heat will pass through in an hour or something like that.
anyway the next column shows it's conductance, which i think just expresses the conductivity of that material in a certain thickness, so you divide by the thickness. the next column, resistance, is the opposite of conductance. but then i don't understand how they jump from there and conclude that the temperature is going through drop 4 degrees through the gypsum plaster. I'm not sure how they get there.
can anyone help explain this to me?
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