Calculating Deceleration and Stopping Time for Margo's Corvette

[almost__overnow]

Margo's Corvette brakes from 32 m/s to 8.0m/s in 6.0 seconds. What is the average deceleration?

If the car continued decelerating at this rate, how long would it take to stop?

i just need to know how to do it cause my answers never came out right.

 

[d_leet]

Can you show us some work, so that we can see where you're having problems.

 

[kyle8921]

To calculate the average deceleration, we can use the formula a = (vf - vi)/t, where a is acceleration, vf is final velocity, vi is initial velocity, and t is time. In this case, vf = 8.0 m/s, vi = 32 m/s, and t = 6.0 s. Substituting these values into the formula, we get a = (8.0 m/s - 32 m/s)/6.0 s = -4 m/s^2. This means that the average deceleration of Margo's Corvette is 4 m/s^2.

To calculate the stopping time, we can use the formula vf = vi + at, where vf is final velocity, vi is initial velocity, a is acceleration, and t is time. In this case, vf = 0 m/s (since the car is stopping), vi = 32 m/s, and a = -4 m/s^2 (since the car is decelerating). Substituting these values into the formula, we get 0 m/s = 32 m/s + (-4 m/s^2)t. Solving for t, we get t = 8 seconds. This means that if the car continued decelerating at the same rate, it would take a total of 8 seconds to come to a complete stop.

It is important to note that these calculations assume that the car is decelerating at a constant rate. In reality, the deceleration may vary depending on factors such as road conditions and the efficiency of the car's brakes.