- #1
jjjsarnis
- 15
- 0
the problem reads:
a uniform bridge 20 m long and weighing 400,000 N is supported by two pillars located 3 m from each end. if a 19,600 N car is parked 8 m from one end of the bridge, hoe much force does each pilliar exert?
i was thinking about using something like (W1)(d1) = (W2)(d2) that we used early for a seesaw problem. also if the sum of forces could be added up to equal zero and place it in equilibrium.
thanks for any help
a uniform bridge 20 m long and weighing 400,000 N is supported by two pillars located 3 m from each end. if a 19,600 N car is parked 8 m from one end of the bridge, hoe much force does each pilliar exert?
i was thinking about using something like (W1)(d1) = (W2)(d2) that we used early for a seesaw problem. also if the sum of forces could be added up to equal zero and place it in equilibrium.
thanks for any help